1/2(-9.81)t^2+5t+10=t

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Solution for 1/2(-9.81)t^2+5t+10=t equation: 



1/2(-9.81)t^2+5t+10=t

We move all terms to the left:

1/2(-9.81)t^2+5t+10-(t)=0



Domain of the equation: 2(-9.81)t^2!=0

t∈R



We add all the numbers together, and all the variables

4t+1/2(-9.81)t^2+10=0

We multiply all the terms by the denominator


4t*2(-9.81)t^2+10*2(-9.81)t^2+1=0

Wy multiply elements

8t^2(-+20t(-+1=0

We use the square of the difference formula

8t^2(-20t(-1=0

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